How to find the diagonal of a parallelogram ?
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Answer:
Diagonal of Parallelogram Formula
Where, p,q are the diagonals. a,b are the parallel sides.
\LARGE p=\sqrt{a^{2}+b^{2}-2ab\cos (A)}=\sqrt{a^{2}+b^{2}+2ab\cos (B)}
\LARGE q=\sqrt{a^{2}+b^{2}+2ab\cos (A)}=\sqrt{a^{2}+b^{2}-2ab\cos (B)}
\LARGE p^{2}+q^{2}=2(a^{2}+b^{2})
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Step-by-step explanation:
In a parallelogram, the diagonals bisect each other, so you can set the labeled segments equal to one another and then solve for . \displaystyle 20 - 3x = 2x - 4 \rightarrow 24 = 5x \rightarrow 4.8 = x. Then, substitute 4.8 for in each labeled segment to get a total of 11.2 for the diagonal length.
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