Question

how to find the dimension of permittivity of vacuum

Answer 1

PEMITTIVITY= (CHARGE)^2 /(FORCE)*(DISTANCE)^2

 =[TA]^2 / [MLT^ -2] [L]^2

 =[TA]^2 / [ML^3T^ -2]

 =[M^ -1 L^ -3 T^2+2 A^2]

= [M^ -1 l^ -3 T^4 A^2]

Answer 2

Hey !!!

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Here is ur answer with solution

Please see attachment
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