Question

how to find the distance of the image when an object is placed on the principal axis at a distance of 10cm infront o0f a concave mirror whose radius of curture is 8cm

Answer 1

$here \: u = - 10cm \: and \: f = - 4 \: \\ then \: using \: lens \: formula \: \frac{1}{ v } + \frac{1}{u} = \frac{1}{f } \\ \frac{1}{v} + \frac{1}{ - 10} = \frac{1}{ - 4 } \\ v = - \frac{20}{3} (ans)$