how to find the equation of altitude of triangle from A to side BC
Answers
Step-by-step explanation:
The altitude passing through the vertex A intersect the side BC at D.
AD is perpendicular to BC.
Slope of BC = (y2 - y1)/(x2 - x1)
= (3 - (-2))/(12 - 10)
= (3 + 2)/2
= 5/2
Equation of the altitude passing through the vertex A :
(y - y1) = (-1/m)(x - x1)
A(-3, 0) and m = 5/2
(y - 0) = -1/(5/2)(x - (-3))
y = (-2/5) (x + 3)
5y = -2x - 6
2x + 5y + 6 = 0
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Step-by-step explanation:
The altitude passing through the vertex A intersect the side BC at D.
AD is perpendicular to BC.
Slope of BC = (y2 - y1)/(x2 - x1)
= (3 - (-2))/(12 - 10)
= (3 + 2)/2
= 5/2
Equation of the altitude passing through the vertex A :
(y - y1) = (-1/m)(x - x1)
A(-3, 0) and m = 5/2
(y - 0) = -1/(5/2)(x - (-3))
y = (-2/5) (x + 3)
5y = -2x - 6
2x + 5y + 6 = 0