How to find the equation of altitude of triangle if the equation of two sides is given formula
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To find the equation of the altitude of a triangle, we examine the following example: Consider the triangle having vertices A(−3,2)A(−3,2), B(5,4)B(5,4) and C(3,−8)C(3,−8).

First we find the slope of side ABAB:
4−25−(−3)=25+3=144−25−(−3)=25+3=14
The altitude CDCD is perpendicular to side ABAB.
The slope of
CD=−1slopeofAB=−4CD=−1slopeofAB=−4
Since the altitude CDCD passes through the point C(3,−8)C(3,−8), using the point-slope form of the equation of a line, the equation of CDCD is
y−(−8)=−4(x−3)⇒y+8=−4x+12⇒4x+y−4=0
Read more: https://www.emathzone.com/tutorials/geometry/equation-of-altitudes-of-triangle.html#ixzz5avk09XV2

First we find the slope of side ABAB:
4−25−(−3)=25+3=144−25−(−3)=25+3=14
The altitude CDCD is perpendicular to side ABAB.
The slope of
CD=−1slopeofAB=−4CD=−1slopeofAB=−4
Since the altitude CDCD passes through the point C(3,−8)C(3,−8), using the point-slope form of the equation of a line, the equation of CDCD is
y−(−8)=−4(x−3)⇒y+8=−4x+12⇒4x+y−4=0
Read more: https://www.emathzone.com/tutorials/geometry/equation-of-altitudes-of-triangle.html#ixzz5avk09XV2
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