Question

how to find the equivalent weight of K4[Fe(CN)6] in the reaction
K4[Fe(CN)6]--->(K^+ ) + (Fe^+3) +CO2+(NO3^-1).If the molar mass of K4[Fe(CN)6] is M

Answer 1

Answer:

hey mate here is your answer ❤️

first you have to find the valence factor for the Fe in K4[Fe(CN)6]

oxidation state of Fe is= +2

valence factor=3-2=1

Equivalent weight=M/1=M

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