how to find the first 15 multiples of 8
Answers
Answered by
5
The first 15 multiplies of 8 are 8,16,24,32,40,48,56,64,72,80,88,96,104,112,120...
Answered by
0
The 8 multiples of 8 are
8, 16, 24, 32, 40, 48, 56, 64
These are in A.P. having first term is 8
Therefore,
first term=8
common difference=8 (second term - first term)
(16 - 8 = 8)
n=15
Sn=?
Sn= n/2[2a + (n-1)d]
Sn=15/2[2(8) + (15 - 1)8]
=15/2[16 + (14)(8)]
=15/2[16 + 112]
=15 × 128/2
=15 × 64
Sn=960
8, 16, 24, 32, 40, 48, 56, 64
These are in A.P. having first term is 8
Therefore,
first term=8
common difference=8 (second term - first term)
(16 - 8 = 8)
n=15
Sn=?
Sn= n/2[2a + (n-1)d]
Sn=15/2[2(8) + (15 - 1)8]
=15/2[16 + (14)(8)]
=15/2[16 + 112]
=15 × 128/2
=15 × 64
Sn=960
Similar questions