Question

How to find the first number divisible by 3 between 500 and 600?

Answer 1

Answer:

in500, we split it into 3individual digits i.e,5, 0, 0

since 0 doesn't have the value,

we take 5

since 5 is not a multiple of 3

we say that 500 is not divisible by 3

in600, 6 is a multiple of 3 so 600 can be divided by 3

Answer 2

Answer:

your answer is 501 firstly you have to divide 500 by 3

see how?

when you are dividing the see how much we have to add the

first divide two digit from starting and  see how much we have to add the

here we have to add 1 in 500

Step-by-step explanation:  EXTRA EXPLANATION TO YOU FOR NUMBER            DIVISIBLE BY ANY NUMBER

to find total number

L = A + (N - 1)*D,

Here, L is the last digit,

A is the first digit,

N is the number of digits in between, and D is the difference.

So, A = 501(after 500 this is the first number which is completely divisible by 3)

L = 600 (last number which is divisible by 3 completely in 500–600 range).

D = 3, and N we need to calculate.

600=501+(N-1)*3

600-501=3N-3

99+3=3N

102=3N

N=102/3

total number divisible by 3 from 500-600 N=34