Math, asked by IshaanShukla, 10 months ago

how to find the height of a parallelogram in co-ordinate geometry using the equations of it's sides ​

Answers

Answered by badatyasujata756
0

area of a parallelogram= bade*height.

if there are area is given by putting the value of area and base we can calculate the height of parallelogram.

Answered by vikhyat04
0

EXAMPLE

Given A(4,-2) B(7,2) C(0,9) and D(-3,5).

Area of the triangle ABC = 1/2 (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)

                                         = 1/2(4(2-9) + 7(9+2)

                                         = 49/2.

Area of parallellogram = 2 * 49/2 = 49 square units.

Base of the parallelogram AB = root(x1 - x2)^2 + (y1 - y2)^2

                                                  = root (4 - 7)^2 + (-2-2)^2

                                                  = root 9 + 16

                                                 = root 25

                                                 = 5.

The height of the parallelogram = 49/5.

NOTE:-Coordinates of a parallelogram tell the length of each side using formula ((x2-x1)^2 +(y2-y1)^2)^0.5

Then, find area and then, using normal formula, get ht as base is given...

That's how you find ht....

PLEASE MARK BRAINIEST

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