how to find the height of a parallelogram in co-ordinate geometry using the equations of it's sides
Answers
area of a parallelogram= bade*height.
if there are area is given by putting the value of area and base we can calculate the height of parallelogram.
EXAMPLE
Given A(4,-2) B(7,2) C(0,9) and D(-3,5).
Area of the triangle ABC = 1/2 (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)
= 1/2(4(2-9) + 7(9+2)
= 49/2.
Area of parallellogram = 2 * 49/2 = 49 square units.
Base of the parallelogram AB = root(x1 - x2)^2 + (y1 - y2)^2
= root (4 - 7)^2 + (-2-2)^2
= root 9 + 16
= root 25
= 5.
The height of the parallelogram = 49/5.
NOTE:-Coordinates of a parallelogram tell the length of each side using formula ((x2-x1)^2 +(y2-y1)^2)^0.5
Then, find area and then, using normal formula, get ht as base is given...
That's how you find ht....