Chemistry, asked by shwetajain9488, 1 year ago

How to find the hybridization of [zncl4]^-2?

Answers

Answered by IshanRocks

Electronic configuration of Zn2+ is d10. Hence d orbital will not be available. So the next 4s and 4p orbitals will be used. So hybridisation is sp3, and thus tetrahedral structure.

Answered by riya9896

Explanation:

Electronic configuration of Zn2+ is d10. Hence d orbital will not be available. So the next 4s and 4p orbitals will be used. So hybridisation is sp3, and thus tetrahedral structure.

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