how to find the interior angle of a regular polygon
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hey!!!
The formula for calculating the sum of the interior angles of a regular polygon is the following:-
1st method:-
![(n - 2) \times 180 (n - 2) \times 180](https://tex.z-dn.net/?f=%28n+-+2%29+%5Ctimes+180)
n is the number of sides of the polygon.
Example if the figure is a decagon ( a shape that has 10 sides).
So:-
![(n - 2) \times 180 (n - 2) \times 180](https://tex.z-dn.net/?f=%28n+-+2%29+%5Ctimes+180)
![(10 - 2) \times 180 (10 - 2) \times 180](https://tex.z-dn.net/?f=%2810+-+2%29+%5Ctimes+180)
![8 \times 180 8 \times 180](https://tex.z-dn.net/?f=8+%5Ctimes+180)
![1440 1440](https://tex.z-dn.net/?f=1440)
Or ( second method):-
180-360/n
n= number of sides.
If figure is a pentagon so it means it has five sides so:-
180-360/5
=180-72
=108
Hope u understand!!!...
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The formula for calculating the sum of the interior angles of a regular polygon is the following:-
1st method:-
n is the number of sides of the polygon.
Example if the figure is a decagon ( a shape that has 10 sides).
So:-
Or ( second method):-
180-360/n
n= number of sides.
If figure is a pentagon so it means it has five sides so:-
180-360/5
=180-72
=108
Hope u understand!!!...
Mark as brainliest...
Don't forget to follow me...
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