Question

how to find the lenght of side of rhombus whose diagonals are 12cm and 16 cm

Answer 1

Given ,

diagonal 1 = 12 cm

diagonal 2 = 16 cm

Let ,

formula of rhombus = 1/2 × d1 × d2

Now ,

==> 1/2 × 12 × 16

==> ( cancellation of 1/2 and 12 )

==> 6 × 16 = 96

therefore , length of side of rhombus = 96 cm

Answer 2

Given

d¹ = 12 Cm

d² = 16 Cm

We Find

Side of Rhombus

According to the question

We using Pythagoras theorem

$= \sqrt{ {12}^{2} }+ \sqrt{ {16}^{2} } \\ \\ = \sqrt{144} + \sqrt{256} \\ \\ = \sqrt{400} \\ \\ = 20 \: cm$

Hence, side of rhombus is 20 cm