how to find the no; of perfect squares in between two no:s?
Answers
Answer:
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Answer:
HEY MATE HERE'S YOUR ANSWER
Step-by-step explanation:
1. Try this - let x and be two numbers then find z= [sqrt(xy)], next find p= [sqrt(z)]. Now p^2 is the required square.
Example: need to find perfect square between 8717 and 9587.
Step 1: z = sqrt(8717*9587) = 9141.
Step 2: p= [sqrt(9141)] = [95.61] = 95.
So 95^2 = 9025 is ready square.
Example 1. Suppose there are two numbers 86 and 104 and you are required to find a number them which is a perfect square.
Find the square roots of 86 and 104. They are 9.2736 and 10.198. Find the integer/s between the two values of square roots which is 10 in this case. So the number is 10^2 = 100.
Example 2. Suppose there are two numbers 8717 and 12451 and you are required to find a number them which is a perfect square.
Find the square roots of 8717 and 9587. They are 93.36 and 97.91. Find the integer/s between the two values of square roots which is 94 to 97 in this case. So the numbers are 94^2, 95^2, 96^2 and 97^2, or 8836, 9025, 9216, 9409
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