Chemistry, asked by tanmoykar03212, 9 months ago

How to find the oxidation number of the chemical equation K2Cr2O7 + H2S + H2SO4= K2SO4 + Cr2(SO4)3+ S+ H2O

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Answered by nithiadk

0

Answer:

K2Cr2O7 + H2S + H2SO4= K2SO4 + Cr2(SO4)3+ S+ H2O

⇒ K2Cr2O7 + 4H2SO4 + 3H2S = K2SO4 + Cr2(SO4)3 + 7H2O + 3S

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