Question

how to find the perimeter of a rectangular piece of glass is 50cm. Find it's area , if it's length is 14cm. .Pls tell me the solution also.plssss

Answer 1

FORMULA FOR PERIMETER.

PERIMETER=2(length+breadth)
50=2(14+b)
50=28+2b
50-28=2b
22=2b
B=11cm

AREA=Length X Breadth
=14X11
=154cm2^

Hope it helps..

Answer 2

$\textbf{\large{\underline{Answer :-}}}$

The area of the Rectangle is $\textbf{154 sq.cm }$

$\textbf{\large{\underline{Explaination :-}}}$

Given :-

Perimeter of Rectangle = 50 cm

Length = 14 cm

To find :-

The area of the Rectangle

Solution:-

To find the area, first we need to find the Breadth of the Rectangle.

$\textbf{Perimeter of Rectangle =}$

$\tt{\Rightarrow2(l + b)}$

$\tt{\Rightarrow2(l + b) = 50}$

$\tt{\Rightarrow2(14 + b) = 50}$

$\tt{\Rightarrow28 + 2b = 50}$

$\tt{\Rightarrow2b = 50 - 28}$

$\tt{\Rightarrow2b = 22 }$

$\tt{\Rightarrow \: b = \dfrac{22}{2} }$

$\tt{\Rightarrow b = 11}$

$\textbf{Breadth = 11cm }$

$\textbf{Area of Rectangle}$

$\tt{\rightarrow length \times breadth}$

$\tt{\Rightarrow11 \times 14}$

$\tt{\Rightarrow154 \: sq.cm}$

$\therefore$The area of the Rectangle is $\textbf{154 sq.cm }$