Question

how to find the perimeter of the square if the area of a right angled triangle formed by two adjacent sides and diagonal of a square is 40.5sq.m.

Answer 1

Answer:

answer

Step-by-step explanation:

In △ABC&△ACH

∠ACB=∠AHC,∠CAB=∠HAC,∠ABC=∠ACH

So △ACH∼△ABC

Similarly △CBH∼△ABC

⟹

AB

BC

=

BC

BH

and

AB

AC

=

AC

AH

⟹BC

2

=AB×BH⋯(1) and AC

2

=AB×AH⋯(2)

(1)+(2)⟹BC

2

+AC

2

=AB×(BH+AH)=AB

2

⟹AB

2

=BC

2

+CA

2

Square of hypotenuse is equal to sum of squares of other two sides

solution