how to find the perimeter of the square if the area of a right angled triangle formed by two adjacent sides and diagonal of a square is 40.5sq.m.
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Answer:
answer
Step-by-step explanation:
In △ABC&△ACH
∠ACB=∠AHC,∠CAB=∠HAC,∠ABC=∠ACH
So △ACH∼△ABC
Similarly △CBH∼△ABC
⟹
AB
BC
=
BC
BH
and
AB
AC
=
AC
AH
⟹BC
2
=AB×BH⋯(1) and AC
2
=AB×AH⋯(2)
(1)+(2)⟹BC
2
+AC
2
=AB×(BH+AH)=AB
2
⟹AB
2
=BC
2
+CA
2
Square of hypotenuse is equal to sum of squares of other two sides
solution
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