how to find the point of intersection of x + 2y = 5 and x - 3y = 7
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Answered by
0
1)substitution method.
x+2y=5 , x-3y=7
x=5-2y .........(1) , x=7+3y .............(2)\
substitute eq .....(1) in eq.....(2)
5-2y=7+3y
-3y-2y=7-5
-5y=2
y=-2/5
substitute y value in eq ......(1)
x=29/5
(x,y)=(29/5,-2/5)
Answered by
0
You can find the point of intersection by solving these two eqn.
x+2y=5
x-3y=7
- + -
_________
5y=-2
⇒y=-2/5
So x=5-2y
x= 5+4/5
⇒x=29/5
So the point of intersextion is (x,y)=(29/5,-2/5)
x+2y=5
x-3y=7
- + -
_________
5y=-2
⇒y=-2/5
So x=5-2y
x= 5+4/5
⇒x=29/5
So the point of intersextion is (x,y)=(29/5,-2/5)
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