Physics, asked by aniruddhmuv3140, 1 year ago

how to find the power consumed by motor from nameplate

Answers

Answered by NightFury
0
A 6 pole 3-phase AC induction motor is delta-connected and has the following rated values on its nameplate:

Frequency: 50 Hz

Power: 22 kW   30 hp

RPM: 970

cosϕcos⁡ϕ (power factor): 0.80

Primer voltage (VlineVline): 380 V

Primer current (IlineIline): 47 A

Since the total power of a 3-phase AC induction motor when delta-connected is

Pt=3–√⋅Vline⋅Iline⋅cosϕPt=3⋅Vline⋅Iline⋅cos⁡ϕ

I calculate the electrical power as

Pt=24.75kWPt=24.75kW

but on the nameplate there are two powers, written as 22 kW and 30 hp (30 hp is 22.37 kW); are they the same thing?

Why am I calculating the power PtPt differently? Are the power ratings on the nameplate mechanical power or electrical power?

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