How to find the Pythagorean triplet
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(3,4,5) ×2 = 8,6,10 and 8,6,10 is also a pythagorean triplet(5,12,13) ×2 = 10,24,26 and 10,24,26 is also a pythagorean triplet
When the side lengths of a right triangle satisfy the pythagorean theorem, these three numbers are known as pythagorean triplets or triples.
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You need to check that out of the 3 values one is the squareroot of the sum of the squares of the other two.
You need to consider the highest number given out of 3 as the sqareroot of the sum of the squares of other two numbers. If the condition is satisfied then it is a Pythagorean triplet otherwise its not.
Eg. Prove that 3,4 and 5 are pythagorean triplets.
Here 5 is the highest no so.
5=[(3*3)+(4*4)]^1/2
5=(9+16)^1/2
5=(25)^1/2
5=5
Hence it is proved.
You need to consider the highest number given out of 3 as the sqareroot of the sum of the squares of other two numbers. If the condition is satisfied then it is a Pythagorean triplet otherwise its not.
Eg. Prove that 3,4 and 5 are pythagorean triplets.
Here 5 is the highest no so.
5=[(3*3)+(4*4)]^1/2
5=(9+16)^1/2
5=(25)^1/2
5=5
Hence it is proved.
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