Question

How to find the range of values of x for which Ln(x^2-2x) is defined

Answer 1

Answer:

ln (2x - x^2):

2x - x^2 > 0

x^2 -2x <0

x(x-2)<0

(x-0)(x-2)<0

x lies in between 0 and 2

x ∈ (0 2)

Step-by-step explanation:

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Answer 2

We know that ln(x) is function which can take only positive values,Hence (2x-x^2) must be greater than zero. Therefore (2x-x^2)>0. Now x(2-x)>0 ie x belongs to (0,2).