how to find the ratio in which the line segment joining the point (-3,10)and (6,-8)is divided by $-1,6)
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Answered by
0
Let the ratio be k:1
Therefore,
-1=(6k-3)/(k+1)
-k-1=6k-3
7k=2
k=2/7
Therefore, the ratio is 2:7
Therefore,
-1=(6k-3)/(k+1)
-k-1=6k-3
7k=2
k=2/7
Therefore, the ratio is 2:7
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ur answer is attached mate...
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