how to find the ratio in which the line segment joining the points (-3, 10) and (6, -8) divided by (1, -6)
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Step-by-step explanation:
Using the section formula, if a point (x,y) divides the line joining the points (x1,y1) and (x2,y2) in the ratio m:n, then
(x,y)=(m+nmx2+nx1,m+nmy2+ny1)
Let the point P(−1,6) divides the line joining A(−3,10) and (6,−8) in the ratio k:1
Then, by section formula,
the coordinates of P are (k+16k−3,k+1−8k+10)
⇒(−1,6)=(k+16k−3,k+1−8k+10)
∴k+16k−3=−1⇒6k−3=−k−1⇒6k+k=3−1⇒7k=2∴ k=
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