How to find the reading of the ammeter? Are all resistors in parallel or series or series-parallel combination is there. Thank you.
Attachments:
Answers
Answered by
1
According to ur qsn :-
⇒Since all the resistances are connected in parallel , So net resistance will be
1/R = 1/9 × 9
⇒R = 1Ω
Now , V = IR
⇒ 9 = I × 1
⇒I = 9A
∴So ammeter will show a reading of 9A
⇒Since all the resistances are connected in parallel , So net resistance will be
1/R = 1/9 × 9
⇒R = 1Ω
Now , V = IR
⇒ 9 = I × 1
⇒I = 9A
∴So ammeter will show a reading of 9A
AlwaysTrying:
I thought this too but the answer is 5A so maybe the answer in the book is misprinted. Thank you.
Similar questions