how to find the reduced form of two numbers
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by dividing it from its divisible example:if the number is 16÷2=8÷2=4÷2=1
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let the numbers is 72 and 60
write the number in ratio form=72:60 divide both numbers by its HCF
72/12=6
60/12=5
thus the reduced form of 72 :60 is 6:5
write the number in ratio form=72:60 divide both numbers by its HCF
72/12=6
60/12=5
thus the reduced form of 72 :60 is 6:5
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