How to find the solution of,
CaCl2+Na2SO4
Explain how to find solution!
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Answer:
calcium sodium sulphate
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Answer:
Reaction type: double replacement
CaCl2 (aq) + Na2SO4 (aq) -----> CaSO4 + 2NaCl
.025 L * .05 M = 1.25 *10^-3 mols of CaCl2
.075 L * .01 M = 7.50 *10^-4 mols of Na2SO4
Find the limiting reagent
7.50 *10^-4 mols of Na2SO4 * (1 mol CaCl2/1 mol Na2SO4) = 7.50 *10^-4 CaCl2 able to react with Na2SO4 and since you have extra CaCl2, it is in excess and the limiting reagent is Na2SO4
7.50 *10^-4 mols Na2SO4 reacts with 7.50 *10^-4 CaCl2 to product 7.50 *10^-4 mols of CaSO4
7.50 *10^-4 mols of CaSO4 * (136.142 g / mol CaSO4) = 0.102 g of CaSO4 are in the precipitate
Explanation:
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