how to find the total number of fundamental particles in one atom of C14/6 is
Answers
Answered by
11
Answer:
The mass no. Z will tell u about the total no. of protons and neutrons and in a neutral atom, the no. of electrons is equal to no. of protons.
In C-14 isotope,
n + p= 14
e = 6
Total fundamental particles= n + p + e
= 14 + 6
= 20
PLEASE MARK AS BRAINLIEST.
Answered by
3
In the given element c14/6, the fundamental particles are listed below
Atomic mass= A=14
Atomic number=Z=6
Number of electrons=e= 6
Number of protons=p=6
Number of neutrons=n=8
Therefore the total number of fundamental particles in one atom of C14/6 is= No. of electrons+No of protons+ No. of neutrons
=e+p+n
=6+6+8
=20
Similar questions