Question

how to find the value of (5-3i) ^3​

Answer 1

Answer:

by using identity

(a+b)³=a³+b³+2a²b+2ab²

=5³+(3i)³+2(5)²(3i)+2(5)(3i)²

=125+9i+150i+45i

=125+204i

hope it helped u ...plz mark as the brainliest.....thanks

Answer 2

Answer:

$(5 - 3i)^{3} \\ = (5)^{3} - (3i)^{3} - 3(5)^{2} \times 3i + 3 \times 5(3i)^{2} \\ = 125 - 27i^{3} - 225i + 135i^{2} \\ 125 - 27( - 1)i - 225i + 135( - 1) \\ = 125 + 27i - 225i - 135 \\ = - 10 - 198i$