How to find the value of cot1 degree
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Step-by-step explanation:
Let cot θ = x (- ∞ < x < ∞) then θ = cot−1 x.
Here θ has infinitely many values.
Let – π2 ≤ α ≤ π2, where α is positive or negative smallest numerical value of these infinite number of values and satisfies the equation cot θ = x then the angle α is called the principal value of cot−1 x.
Again, if the principal value of cot−1 x is α (α ≠ 0, – π/2 ≤ α ≤ π/2) then its general value = nπ + α.
Therefore, cot−1 x = nπ + α, where, (α ≠ 0, – π/2 ≤ α ≤ π/2) and ( - ∞ < x < ∞ ).
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