Question

how to find the volume of a cork floating on water​

Answer 1

Answer:

Mass of cork = (10 + x ) * 0.15 g

volume of displaced water = x

mass of displaced water = x * 1 = x (density of water = 1 g cm-3)

As per the Archemedes' principle

weight of cork = weight of water displaced

x g= (1.5 + 0.15 x)g

x = 1.5 + 0.15 x

x = 1.5 / 0.85 = 1.765 cm3

total volume of the cork = 10+1.765 = 11.765 cm3

Mass of cork = 11.765 * 0.15 = 1.765 g

Answer 2

Answer:

volume of the cork =11.765cm^2

Explanation:

volume of displayed water=x

mass of displayed water =x*1 =x

(density of water= 1g cm-3)

As per the archemeds' principle

weight of cork=weight of water displayed

x g=(1.5 +0.15x)g

x=1.5/0.85 =1.765

10 +1.765

=11.675

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