How to find the zeroes of quadratic polynomial if on of it zeros are given
Answers
YOUR QUESTION IS INCORRECT THIS ID CORRECT QUESTION
Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.
(i)1/4 , -1 (ii) ?2 , 1/3 (iii) 0, ?5 (iv) 1,1 (v) -1/4 ,1/4 (vi) 4,1
(i)1/4, -1
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² �(1/4)x -1� = 0
Multiply by 4 to remove denominator we get
4x² �- �x �-4 �= 0
(ii) ?2 , 1/3
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² �(?2)x� + 1/3� = 0
Multiply by 3 to remove denominator we get
3x²� - 3?2 x + 1� = 0
(iii) 0, ?5
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² �(0)x� + ?5� = 0
simplify it we get
x²�� + ?5� = 0
(iv) 1,1 �
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² �(1)x� + 1� = 0
simplify it we get �
x²� - �x + 1� = 0
(v) -1/4 ,1/4
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² �(-1/4)x� + 1/4� = 0
multiply by 4 we get
4x²�� +� x + 1� = 0
(vi) 4,1
Now formula of quadratic equation is
x²-(Sum of root)x + (Product of root) = 0
Plug the value in formula we get
x² �(4)x� + 1 = 0
x^2 �4x� + 1 = 0