Question

how to find the zeroes of the polynomial 4u^2+8u please also include the method
answer only if you know ​

Answer 1

here is exact answer for your question

hope its help you :-)

i find it for you

Answer 2

Explanation:

4u^2 + 8u = 0

4u(u + 2) = 0. [taking 4u as common]

1st zero ---- 4u(u + 2) = 0

u + 2 = 0

u = -2

2nd zero ----- 4u(u + 2) = 0

4u = 0

u = 0

Hence, zeros of the polynomial are (-2,0)