Question

how to find these question which are circled out there pls

Answer 1

I don't know circled out please

Answer 2

if you are class 10, then don't do it because it requires a class 11th theorem

Anyways here is your answer:
Given PAB is the secant and PT is the tangent to the circle with centre O Draw ON ⊥�ABTherefore, AN = BN Also we have PT2�= PA × PB [By tangent secant property] ---- (1)Consider ΔONA OA2�= ON2�+ AN2� ---- (2) Similarly in�ΔPTO OP2�= OT2�+ PT2That is PT2�= OP2�- OT2 = ON2�+ PN2�- OA2� [Since OA = OT (radii)] = ON2�+ PN2�– ON2�– AN2 ⇒ PT2�= PN2�– AN2�----(3) From (1) and (3), we get �PA × PB = PN2�– AN2
Hope it helps!
Mark my answer as brainliest!!