Question

how to find this 64 ^ -(2/3)​ please explain the process

Answer 1

Answer:

${(64)}^{ - \frac{2}{3} } \\ = ( {( {64})^{ \frac{2}{3} } })^{ - 1} \\ = \frac{1}{ {(64)}^{ \frac{2}{3} } } \\ = \frac{1}{ { (\sqrt[3]{64)} }^{2} } \\ = \frac{1}{ {4}^{2} } \\ = \frac{1}{16}$