Question

how to find this one?​

Answer 1

Answer:

Step-by-step explanation:

For (1) in ΔABD and ΔACD

AB = AC (ΔABC is isosceles triangle)

BD = DC (ΔDBC is isosceles triangle)

AD = AD (Common side in both triangles)

So from SSS congruence rule, we can say

ΔABD ≅ ΔACD

For (2) in ΔABP and ΔACP

AB = AC (ΔABC is isosceles triangle)

AP = AP (Common side in both triangles)

BP = PC (P will be mid point for isosceles  triangle)

So from SSS congruence rule, we can say

ΔABP ≅ ΔACP

Answer 2

Answer:

Hey user kindly refer to the attachment

Step-by-step explanation:

hope it helps