how to find this please explain
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1
put x= -a then solve equation.
as(x-a) =0
=>x= -a
as(x-a) =0
=>x= -a
Answered by
1
Given Equation is f(x) = x^3 + ax^2 - 2x + a + 4.
Given (x + a) is a factor of f(x).
By remainder theorem,
x + a = 0
x = -a.
Substitute x = -a in f(x), we get
f(-a) = (-a)^3 + a(-a)^2 - 2(-a) + a + 4 = 0
-a^3 + a^3 + 2a + a + 4 = 0
3a + 4 = 0
3a = -4
a = -4/3.
Hope this helps!
Given (x + a) is a factor of f(x).
By remainder theorem,
x + a = 0
x = -a.
Substitute x = -a in f(x), we get
f(-a) = (-a)^3 + a(-a)^2 - 2(-a) + a + 4 = 0
-a^3 + a^3 + 2a + a + 4 = 0
3a + 4 = 0
3a = -4
a = -4/3.
Hope this helps!
siddhartharao77:
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