Question

How to find three consecutive even integers whose sum is 72

Answer 1

Explanation:

Let the first integer be n then the next even is n+2 and then n+4

Sum means to add:

⇒n+n+2+n+4=72

Simplifying...

⇒3n+6=72

⇒3n=66

⇒n=22

Hence integers are n , n+2 , n+4

⇒22,24,26

Answer 2

let the first even no. be a
next two even nos. will be
a+2 and a+4

according to the question

a+ a+2+ a+4=72
3a+6=72
3a=72-6=66
a=66/3=22

the nos. are
a=22
a+2 =24
and a+4=26