Question

how to find total resistance in a series parallel circuit

Answer 1

$Let\ the\ resistors\ are\ R_1,\ R_2,\ R_3, ....,R_n \\ If\ they\ are\ connected\ in\ parallel\ in\ a\ circuit,\ effective\ resistance$

$\frac{1}{R_p} = \frac{1}{R_1} +\frac{1}{R_2} +\frac{1}{R_3} +....+\frac{1}{R_n}$

$If\ they\ are\ connected\ in\ series\ in\ a\ circuit,\ effective\ resistance$

$R_s =R_1+R_2+R_3+.....+R_n$

Answer 2

let the total no of resistors be n
so if they are connected in series , equivalent resistance is :
R=R₁+R₂+R₃......$R_{n}$
and if they are connected in parallel,the equivalent resistance:
$\frac{1}{R} = \frac{1}{ R_{1} } \frac{1}{ R_{2}}...... \frac{1}{ R_{1} {n}}$