how to find unit digit in expression 55^725+73^5810+22^853
Answers
Answered by
4
Answer:
6
Step-by-step explanation:
by cyclicity of 5,3 and 2,
55 unit digit=5.
5^725=5. ..(5^n is always ends with 5)
Unit digit of73 is 3
3^5810 divide the power by 4i.e 5810/4 remainder=2
3^(4k+2) unit digit is 9. .
Unit digit of 22 is 2
2^853 can be expressed as 2^(4k+1)
And unit digit of 2^(4k+1) is 2...
So,the unit digit of sum of
55^{725}+73^{5810}+22^{853}
Is 5+9+2=...6.
Hence,6 is the answer.
Answered by
1
Answer:
8.0503970E10825
Step-by-step explanation:
try it on Microsoft math calculator
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