How to find value of y and z here
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Shravana1:
Detive that formula
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Here is the solution :
To find x, Adding all the numbers isn't good There is a formula we know, That is sum of numbers from 1 to n is n(n+1)/2,
Similarly We have formulas for Sum of Squares and sum of cubes !.
(1) Sum of Squares = [(n)(n+1)(2n+1)/6]
(2) Sum of cubes = [(n)²(n+1)²/4]
Now,
Here comes your answer :
To find value of y, We need to do the following :
[(30)(31)(61)/6] - [(15)(16)(31)/6]
i.e Sum of 30 squares - Sum of 15 squares !.
To find z, We need to the following :
[(50)²(51)²/4] - [(30)²(31)²/4]
I.e Sum of 50 cubes - sum of 31 cubes !.
If you don't believe the formula, Check it out by Keeping in values !
Hope you understand, Have a Great day :),
Thanking you, Bunti 360 !..
To find x, Adding all the numbers isn't good There is a formula we know, That is sum of numbers from 1 to n is n(n+1)/2,
Similarly We have formulas for Sum of Squares and sum of cubes !.
(1) Sum of Squares = [(n)(n+1)(2n+1)/6]
(2) Sum of cubes = [(n)²(n+1)²/4]
Now,
Here comes your answer :
To find value of y, We need to do the following :
[(30)(31)(61)/6] - [(15)(16)(31)/6]
i.e Sum of 30 squares - Sum of 15 squares !.
To find z, We need to the following :
[(50)²(51)²/4] - [(30)²(31)²/4]
I.e Sum of 50 cubes - sum of 31 cubes !.
If you don't believe the formula, Check it out by Keeping in values !
Hope you understand, Have a Great day :),
Thanking you, Bunti 360 !..
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