Question

How to find values of trigonometric ratios for some specific angles​

Answer 1

Step-by-step explanation:

Let ABC be an equilateral triangle whose sides have length a (see the figure given below). Draw AD perpendicular to BC, then D bisects the side BC. Now, in right triangle ADB, ∠BAD = 30° and BD = a/2. Hence, we can find the trigonometric ratios of angle 30° from the right triangle ADB.

Answer 2

Answer:

Trigonometric ratios of specific angles can be learnt by an easy technique..

Write 0,1,2,3,4 Then divide each by 4. Then find their square roots… Which will be the first T- ratios of specific angles. I'm showing here the method..

First write specific angles in order 0°, 30°, 45°, 60°, 90° horizontally. And write sin, cos, tan, cot, sec, cosec vertically…

●[A] Write 0, 1, 2, 3, 4

Then 0/4, 1/4, 2/4, 3/4, 4/4

●[B] find the square roots now..

0, 1/2, 1√2, √3/2, 1 … These are the values of sin0°, sin30°, sin45°, sin60°, sin90°

●[C] Then , reverse the order. ie 1, √3/2, 1/√2, 1/2, 0. These are the values of cos0°, cos30°, cos45°, cos60°, cos90°.

●[D]Then , divide the first row values by the second row values.. You get tan values then. Like, while dividing we get 0, 1/√3, 1, √3, not defined… These will be the values of tan0°, tan30°, tan45°, tan60°, tan90°

●[E]Then lastly take the reciprocals of sin values. You get Cosec values then.

Reciprocals of Cos values will give you sec values.

And reciprocals of tan values will give you Cot values.

●●●PS! Or else simply learn by heart only the top row values, Then reverse the order. Then divide. Then reciprocals. That covers the whole table.. :) Easy…:)

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