How to find vertical and horizontal asymptotes using limits?
Answers
Answer:
Finding Horizontal Asymptotes of Rational Functions
If both polynomials are the same degree, divide the coefficients of the highest degree terms. ...
If the polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote.
For e. G.
Find all horizontal asymptote(s) of the function f(x)=x2−xx2−6x+5 and justify the answer by computing all necessary limits.
Find all horizontal asymptote(s) of the function f(x)=x2−xx2−6x+5 and justify the answer by computing all necessary limits.Also, find all vertical asymptotes and justify your answer by computing both (left/right) limits for each asymptote.
Find all horizontal asymptote(s) of the function f(x)=x2−xx2−6x+5 and justify the answer by computing all necessary limits.Also, find all vertical asymptotes and justify your answer by computing both (left/right) limits for each asymptote.MY ANSWER so far..
Find all horizontal asymptote(s) of the function f(x)=x2−xx2−6x+5 and justify the answer by computing all necessary limits.Also, find all vertical asymptotes and justify your answer by computing both (left/right) limits for each asymptote.MY ANSWER so far..For the Horizontal asymptote, I simply looked at the coefficients for both the numerator and the denominator. Both are 1 so 11 gives me y=1 as the Horizontal asymptote however I don't know how I would justify it with a limit. If i take the limit of f(x), what will x approach? ∞ or −∞?
Find all horizontal asymptote(s) of the function f(x)=x2−xx2−6x+5 and justify the answer by computing all necessary limits.Also, find all vertical asymptotes and justify your answer by computing both (left/right) limits for each asymptote.MY ANSWER so far..For the Horizontal asymptote, I simply looked at the coefficients for both the numerator and the denominator. Both are 1 so 11 gives me y=1 as the Horizontal asymptote however I don't know how I would justify it with a limit. If i take the limit of f(x), what will x approach? ∞ or −∞?For the vertical asymtote, I set the denominator equal to 0 and got x=5 and x=1 as the vertical asymptotes. However, I dont know how I would justify my answer using limits..
Step-by-step explanation: