Question

how to find whether 4, 5, 6 is a Pythagorean triplet?

Answer 1

first you have to do the square of these number

let p=4

b=5

h=6

as we know,p^2+b^=h^2

4^2+5^2=6^2

16+25≠36

so it's not a Pythagorean triplet.

Answer 2

HEY FRIEND ☺

HERE IS YOUR ANSWER

Q. HOW TO FIND WHETHER THE GIVEN SET OF NUMBERS IS A PYTHAGOREAN TRIPLET OR NOT?

ANS. USING H²=P²+B²

Where we take the largest number from the given set of numbers as H and the other two numbers as P and B

Then putting the values we verify for :

H²=P²+B²

If LHS comes equal to RHS, then the given set if numbers is a Pythagorean triplet otherwise not.

LET'S APPLY IT HERE IN YOUR QUESTION NOW.

4,5,6

TAKING H=6, B=5 AND C=4

H²=B²+P²

LHS:
=H²
=6²
=36

RHS :

=B²+P²
=5²+4²
=25+16
=41

LHS≠RHS

SO THE GIVEN SET OF NUMBERS IS NOT A PYTHAGOREAN TRIPLET.

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HOPE THIS HELPS YOU ☺