how to find X using factorisation if the question is 18 + 2 X square + 12 x is equal to zero
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Answered by
1
18+2x²+12x=0,
2(9+x²+6x)=0,
then
x²+6x+9=0,
x²+(3+3)x+9=0,
(x+3)(x+3)=0,
(x+3)²=0,
then
x+3=0,
x=-3
2(9+x²+6x)=0,
then
x²+6x+9=0,
x²+(3+3)x+9=0,
(x+3)(x+3)=0,
(x+3)²=0,
then
x+3=0,
x=-3
Answered by
3
_______________________
Given equation :- 2x² + 12x + 18 = 0
To find the value of x
Now ,
2x² + 12x + 18 = 0
=> 2 ( x² + 6x + 9 ) = 0
=> x² + ( 3 + 3 )x + 9 = 0 [ • 9 = 3 × 3 ]
=> x² + 3x + 3x + 9 = 0
=> x ( x + 3 ) + 3 ( x + 3 ) = 0
=> ( x + 3 ) ( x + 3 ) = 0
=> ( x + 3 )² = 0
=> x + 3 = 0
=> x = - 3 [ ★ Required answer ]
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