how to find zeroes of a quadratic polynomial
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(iii) 6x² – 3 – 7x
Factorize the equation
6x² – 7x – 3
Compare the equation with ax² + bx + c = 0
We get
a = 6 ,b=-7 c= -3
To factorize the value we have to find two value which
sum is equal to b =-7
product is a x c = 6 x -3 = -18
2 and -9 are such number which
sum is 2 – 9 = - 7
product is 2 x - 9 = - 18
So we can write middle term -7x = 2x – 9x
We get
6x² + 2x - 9x - 3 = 0
2x(3x + 1) -3(3x + 1) = 0
(3x + 1) (2x - 3) = 0
3x + 1 = 0 , 2x - 3 = 0
Solve for first zero
3x = - 1
x = -1/3
Solve for second zero
2x-3 = 0
2x = 3
X = 3/2
Factorize the equation
6x² – 7x – 3
Compare the equation with ax² + bx + c = 0
We get
a = 6 ,b=-7 c= -3
To factorize the value we have to find two value which
sum is equal to b =-7
product is a x c = 6 x -3 = -18
2 and -9 are such number which
sum is 2 – 9 = - 7
product is 2 x - 9 = - 18
So we can write middle term -7x = 2x – 9x
We get
6x² + 2x - 9x - 3 = 0
2x(3x + 1) -3(3x + 1) = 0
(3x + 1) (2x - 3) = 0
3x + 1 = 0 , 2x - 3 = 0
Solve for first zero
3x = - 1
x = -1/3
Solve for second zero
2x-3 = 0
2x = 3
X = 3/2
Answered by
3
Hello dear friend
________________
Here is your answer
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The methods to find zeros of a quadratic polynomial are:
1. By factorising the middle term or middle term splitting.
2. By completing the square method
3.By knowing the nature of the roots.
________________
Here is your answer
"""""""""""""""""""""""""""
The methods to find zeros of a quadratic polynomial are:
1. By factorising the middle term or middle term splitting.
2. By completing the square method
3.By knowing the nature of the roots.
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