Question

How to get ans for these question

Answer 1

Given , Side of the lawn = 56

Area of Lawn = (side) ² = 56² = 3136m²

Now, From the figure,
Diameter of circles = Side of square.

So, Diameter = 56m

Radius = 28m .

Area of 2 circular beds = 2(πr²) = 2 (22/7)(28)(28) = 44*4 *28 = 4928 m²

Now, Sum of areas = 3136 + 4928 = 8064 m² [ Answer ]

Answer 2

Side of square ABCD=56 m

AC=BD(diagonals of a square are equal in lengths)

Diagonal of square (AC) =2× side square

=2×56=562 m

OA=OB=21AC=21(562)=282 m

Let OA=OB=r m[radius of the sector]

Area of sector OAB=[360o90o]πr2

=(41)πr2=41×722×(228)2 m2

=[41×722×28×28×2] m2

=1232 m