How to get “massless” equation of motion from the action of Nordstrom scalar field theory?
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There is Nordstrom theory of the particle moving in a scalar field φ(x)φ(x):
S=−m∫eφ(x)ηαβdxαdλdxβdλ−−−−−−−−−−√dλ.S=−m∫eφ(x)ηαβdxαdλdxβdλdλ.
How to get the equation of motion for massless objects? In this case I may introduce new parameter ηαβdxαdλdxβdλ−−−−−−−−√dλ=dτmηαβdxαdλdxβdλdλ=dτm.
But when I try to derive (like this way) the equations of motion, I get
∂αφ=m2ddτ(uαeφ)e−φ.∂αφ=m2ddτ(uαeφ)e−φ.
Unfortunately, this equation doesn't predict the absense of deflection of light. But Nordstrom theory really predicts the deflection of light. So where is the mistake in my reasoning?
Addition.
I got the mistake. By introducing new parameter ττ I must rewrite my equation in a form
∂αφ=1m2ddτ(pαeφ)e−φ.∂αφ=1m2ddτ(pαeφ)e−φ.
So it really preficts no deflection of light.
S=−m∫eφ(x)ηαβdxαdλdxβdλ−−−−−−−−−−√dλ.S=−m∫eφ(x)ηαβdxαdλdxβdλdλ.
How to get the equation of motion for massless objects? In this case I may introduce new parameter ηαβdxαdλdxβdλ−−−−−−−−√dλ=dτmηαβdxαdλdxβdλdλ=dτm.
But when I try to derive (like this way) the equations of motion, I get
∂αφ=m2ddτ(uαeφ)e−φ.∂αφ=m2ddτ(uαeφ)e−φ.
Unfortunately, this equation doesn't predict the absense of deflection of light. But Nordstrom theory really predicts the deflection of light. So where is the mistake in my reasoning?
Addition.
I got the mistake. By introducing new parameter ττ I must rewrite my equation in a form
∂αφ=1m2ddτ(pαeφ)e−φ.∂αφ=1m2ddτ(pαeφ)e−φ.
So it really preficts no deflection of light.
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Hey mate ^_^
You can get “massless” equation of motion from the action of Nordstrom scalar field theory. Check this attachment.
#Be Brainly♥️
You can get “massless” equation of motion from the action of Nordstrom scalar field theory. Check this attachment.
#Be Brainly♥️
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uqpd:
hello frnds
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