How to get new concentration from percent transmittance?
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Transmittance and absorbance are related as follows.
A
=
−
log
(
T
)
Evidently, percent transmittance is simply some fraction of
T
. Absorbance is known to be related to concentration:
A
=
ε
b
c
where
ε
is the molar absorptivity,
b
is the path length, and
c
is the concentration in
M
.
ε
and
b
are CONSTANTS for the same substance.
Therefore:
−
log
(
T
1
)
=
ε
b
c
1
−
log
(
T
2
)
=
ε
b
c
2
And we have:
c
2
c
1
=
log
(
T
2
)
log
(
T
1
)
Thus, the new concentration is:
c
2
=
c
1
log
(
T
2
)
log
(
T
1
)
=
(
26 mg/L
)
log
(
0.617
)
log
(
0.528
)
=
19.66 mg/L
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