Math, asked by questionanswer333, 3 months ago

How to get the number 100 by operating on numbers having altogether just one1 and four 7’s

Answers

Answered by MysticalRainbow
2

Answer:

The Puzzle:

The Puzzle:Using the numerals 1,7,7,7 and 7 (a "1" and four "7"s) create the number 100. As well as the five numerals you can use the usual mathematical operations +, −, ×, ÷ and brackets (). For example: (7+1) × (7+7) = 112 would be a good attempt, but not right, because it is not 100.

Answered by Dhaarini22
2

Answer:

hy

Step-by-step explanation:

Using the numerals 1,7,7,7 and 7 (a "1" and four "7"s) create the number 100.

As well as the five numerals you can use the usual mathematical operations +, −, ×, ÷ and brackets ().

For example: (7+1) × (7+7) = 112 would be a good attempt, but not right, because it is not 100.

177-77 = 100

(7+7) × (7+(1 ÷ 7)) = 100

77/.77 × 1 by Jim Schuller

And all of these are by Robert Veith:

77/.1/7.7

77/7.7/.1

(77 - 7)/7/.1

(77 - 7)/.7/1

(77 - 7)/1/.7

(77 - 7)/.1/7

(7.7 - .7)/.7/.1

.7/(.77 - .7)/.1

(7.7 - .7)/.1/.7

1(7)/(.77 - .7)

7/(.77 - .7)/1

7/.7*7*(1/.7)

1/(.77/77)

7/.7*7/.7*1

1/(.7/7*.7/7)

1/(.7/7)/(.7/7)

(71 - 7/7)/.7

(17 - 7)*(7/.7)

7/(.17 - .7/7)

1/(.7/(77 - 7))

1/((.77 - .7)/7)

(7/7)*7/.1/.7

(7 + 7 - 7)/(.7*.1)

(17 - 7)/(.7/7)

(7/7)*7/.7/.1

1*7*7/(.7*.7)

1/((.7*.7)/(7*7))

(7/.7 + .7)/.1 - 7

7.7/.1/.77

(7/.1 + 7)/.77

(7/.1 + 7 - 7)/.7

(7/.7 + 7 - 7)/.1

7/(7.7 - 7)/.1

7/.1/(7.7 - 7)

7/(7(.71 - .7))

(7/7)/(.71 - .7)

7/(.71 - .7)/7

(7 + 7)/(.7 + .7)/.1

(7 + 7)/.1/(.7 + .7)

7/(.1 + 7 - 7)/.7

1(7/.7)/(.7/7)

(7 + 7 - 7)/.7/.1

7/.7/.1 + 7 - 7

7/.1/.7 + 7 - 7

7/.7/(.1 + 7 - 7)

7/.1/(.7 + 7 - 7)

7/(.7 + 7 - 7)/.1

(7 + 7 - 7)/.1/.7

1*(77 - 7)/.7

(7/.7 - .7)/.1 + 7

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