Question

How to identify the liquid type with the given gauge pressure ?

Answer 1

Answer:

liquid A impure liquid and

liquid B pure liquid ok bro please follow me and make me BRILLIANIST please bro

Answer 2

Answer:

specific gravity of liquid B = 0.99

type of liquid B is usually oil.

Explanation:

Pressure A + ρgh(CD) = Pressure at D

-10890 + (1600 × 9.81 × (3.2 - 2.742) = Pressure at D

-3701.232 = Pressure at D

*assume ρ(air) = 0

Pressure D - ρgh (air) = Pressure at G

-3701.232 -  0 = Pressure at G

-3701.232 = Pressure at G

Pressure G + ρgh(B) = Pressure atmosphere

-3701.232 + ρ(B) × 9.81 × (3.429 - 3.048) = 0

-3701.232 + (3.73761 × ρ(B)) = 0

3.73761 × ρ(B) = 3701.232

ρ(B) = 990.26 kg/m³

specific gravity = density ÷ 1000

S.G liquid B = 990.26 ÷ 1000 = 0.99

I hope this calculation will help & thanks to my mom guys

love y'all!