how to increase Work done by a centripetal force
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centripetal force is rison of linear velocity
VenkatSwaraj:
what?????????
work done by centripetal force is ZERO
for work to be done , there should be non zero component of the displacement in the direction of force.
in case of centripetal force displacement and force mutually perpendicular. so obviously work done is zero.
W=f*d*cos90=0
in case of centripetal force displacement and force mutually perpendicular. so obviously work done is zero.
W=f*d*cos90=0
thankyou fOR ANSWERING
thank
Answered by
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hii....Like other forces , centripetal force is also mass times the acceleration.
However here the acceleration is centripetal acceleration .
Thus Centripetal force can be increased , by increasing the mass , increasing the centripetal acceleration or by increasing both the mass and centripetal acceleration.
While increasing the acceleration ,there is some problem .
The acceleration is governed by two or more familiar formulas
1. a = v^2 /r, 2. a = rω^2 and 3. a = mvω
Hence to increase centripetal acceleration , what should we do ? Increase r? or decrease r ?
We have to say that if r is kept constant, v should be increased or ω should be increased. we need not say both v and ω should be increased.since v = r ω
If we change r , to increase acceleration, we should remember that v = r ω... ... if Centripetal force = m*v^2 / r
where
m = mass
v = velocity of the moving object (linear)
r = radius of the circular motion
From the above relation,centripetal force is inversely proportional to the radius and is directly proportional to the mass and the velocity.
Assuming only the centripetal force is increased and all other forces are kept as it is,then the moving object will gradually move towards the focus point reducing the radius proportional to the increase in centripetal force.....
hope it helps....
thanks
However here the acceleration is centripetal acceleration .
Thus Centripetal force can be increased , by increasing the mass , increasing the centripetal acceleration or by increasing both the mass and centripetal acceleration.
While increasing the acceleration ,there is some problem .
The acceleration is governed by two or more familiar formulas
1. a = v^2 /r, 2. a = rω^2 and 3. a = mvω
Hence to increase centripetal acceleration , what should we do ? Increase r? or decrease r ?
We have to say that if r is kept constant, v should be increased or ω should be increased. we need not say both v and ω should be increased.since v = r ω
If we change r , to increase acceleration, we should remember that v = r ω... ... if Centripetal force = m*v^2 / r
where
m = mass
v = velocity of the moving object (linear)
r = radius of the circular motion
From the above relation,centripetal force is inversely proportional to the radius and is directly proportional to the mass and the velocity.
Assuming only the centripetal force is increased and all other forces are kept as it is,then the moving object will gradually move towards the focus point reducing the radius proportional to the increase in centripetal force.....
hope it helps....
thanks
but
WORK DONE BY CENTRIPETAL FORCE IS ZERO
for work to be done , there should be non zero component of the displacement in the direction of force.
in case of centripetal force displacement and force mutually perpendicular. so obviously work done is zero.
W=f*d*cos90=0
in case of centripetal force displacement and force mutually perpendicular. so obviously work done is zero.
W=f*d*cos90=0
thankyou fOR ANSWERING
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